25z^2/y^2+12y+36=4x^2

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Solution for 25z^2/y^2+12y+36=4x^2 equation: 


D( x )

y^2 = 0

y^2 = 0

y^2 = 0

y^2 = 0

x naleu017Cy do R

x belongs to the empty set

12*y+(25*z^2)/(y^2)+36 = 4*x^2

x belongs to the empty set

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